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Tegesé saka "cómod" ing bausastra Basa Romawi

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PANGOCAP SAKA CÓMOD ING BASA ROMAWI

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APA TEGESÉ CÓMOD ING BASA ROMAWI?

Klik kanggo deleng deifinisi asli saka «cómod» ing bausastra Basa Romawi.
Klik kanggo deleng pertalan otomatis saka definisi ing Basa Jawa.

Definisi saka cómod ing bausastra Basa Romawi

cómod, -Ă adj. (cómmodus umum). Gampang kanggo nggunakake. Tenang lan nyenengake: cody. Bagus lan apik. Relaxed, ora banget kaku: morally humorous. Adv. Cody. \u0026 # X2013; Fals comód (sawise fr. Commode). cómod, -ă adj. (lat. cómmodus). Ușor de întrebuințat. Liniștit și plăcut: vĭață cómodă. Bun la suflet și amabil. Relaxat, nu prea auster: morală cómodă. Adv. În mod cómod. – Fals comód (după fr. commode).

Klik kanggo deleng deifinisi asli saka «cómod» ing bausastra Basa Romawi.
Klik kanggo deleng pertalan otomatis saka definisi ing Basa Jawa.

TEMBUNG BASA ROMAWI KANG KALARAS PADHA KARO CÓMOD


mod
mod

TEMBUNG BASA ROMAWI KANG AWIT KAYA CÓMOD

comlắu
commédia dell´arte
commedia dell´arte
commódo
cómmodo
commonwealth
commonwealth comănuéls
comoára
comoáră
comód
comodánt
comodát
comódă
comoditáte
comodór
comofít
comór
comoráție
comorațiúne
comórnic

TEMBUNG BASA ROMAWI KANG WUSANANÉ KAYA CÓMOD

deadwood
fast-food
líhod
nod
rod
slóbod

Dasanama lan kosok bali saka cómod ing bausastra dasanama Basa Romawi

DASANAMA

Pertalan saka «cómod» menyang 25 basa

PAMERTAL
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PERTALAN SAKA CÓMOD

Weruhi pertalan saka cómod menyang 25 basa nganggo Basa Romawi pamertal multi basa kita.
pertalan saka cómod saka Basa Romawi menyang basa liyané kang kasuguhaké ing perangan iki kajupuk saka pertalan statistik otomatis; ing ngendhi inti unit pertalan yaiku tembung «cómod» ing Basa Romawi.

Pamertal Basa Romawi - Basa Cina

便利
1,325 yuta pamicara

Pamertal Basa Romawi - Basa Spanyol

conveniencia
570 yuta pamicara

Pamertal Basa Romawi - Basa Inggris

convenience
510 yuta pamicara

Pamertal Basa Romawi - Basa India

सुविधा
380 yuta pamicara
ar

Pamertal Basa Romawi - Basa Arab

ملاءمة
280 yuta pamicara

Pamertal Basa Romawi - Basa Rusia

удобство
278 yuta pamicara

Pamertal Basa Romawi - Basa Portugis

conveniência
270 yuta pamicara

Pamertal Basa Romawi - Basa Bengali

সুবিধা
260 yuta pamicara

Pamertal Basa Romawi - Basa Prancis

commodité
220 yuta pamicara

Pamertal Basa Romawi - Basa Malaysia

kemudahan
190 yuta pamicara

Pamertal Basa Romawi - Basa Jerman

Bequemlichkeit
180 yuta pamicara

Pamertal Basa Romawi - Basa Jepang

利便性
130 yuta pamicara

Pamertal Basa Romawi - Basa Korea

편의
85 yuta pamicara

Pamertal Basa Romawi - Basa Jawa

penak
85 yuta pamicara
vi

Pamertal Basa Romawi - Basa Vietnam

sự tiện lợi
80 yuta pamicara

Pamertal Basa Romawi - Basa Tamil

வசதிக்காக
75 yuta pamicara

Pamertal Basa Romawi - Basa Marathi

सोयीसाठी
75 yuta pamicara

Pamertal Basa Romawi - Basa Turki

kolaylık
70 yuta pamicara

Pamertal Basa Romawi - Basa Italia

convenienza
65 yuta pamicara

Pamertal Basa Romawi - Basa Polandia

wygoda
50 yuta pamicara

Pamertal Basa Romawi - Basa Ukrania

зручність
40 yuta pamicara

Basa Romawi

cómod
30 yuta pamicara
el

Pamertal Basa Romawi - Basa Yunani

ευκολία
15 yuta pamicara
af

Pamertal Basa Romawi - Basa Afrikaans

gerief
14 yuta pamicara
sv

Pamertal Basa Romawi - Basa Swedia

bekvämlighet
10 yuta pamicara
no

Pamertal Basa Romawi - Basa Norwegia

bekvemmelighet
5 yuta pamicara

Trèn migunakaké cómod

TRÈN

KEKAREPAN PANGGUNAN ARAN «CÓMOD»

0
100%
Kart kang kapituduh ing dhuwur nuduhaké arang kerepé kagunané aran «cómod» ing negara kang béda-béda.

Tuladha kang kagunakaké ing sastra Basa Romawi, pethikan lan warta babagancómod

TULADHA

BUKU BASA ROMAWI KAKAIT KARO «CÓMOD»

Temukaké kagunané saka cómod ing pilihan bibliografi iki. Buku kang kakait dening cómod lan pethikan cekak kang padha kanggo nyediyakaké panggunané ing sastra Basa Romawi.
1
Two Kinds of Derived Categories, Koszul Duality, and ... - Pagina 46
over C. The thick subcategories of absolutely acyclic CDG-comodules and CDGcontramodules are denoted by Acyclabs(C–comod) ⊂ Hot(C–comod) and Acyclabs(C–contra) ⊂ Hot(C–contra). The quotient categories Dabs(C–comod) and ...
Leonid Positselski, 2011
2
Homological Algebra of Semimodules and Semicontramodules: ...
we want to compute CotorC (N•,M•) is quasi-isomorphic to the complex N• □C M• and has a one-dimensional cohomology space in every degree, even though M• represents a zero object in D(C-comod). Therefore, a more refined version of ...
Leonid Positselski, 2010
3
Rings, Modules, Algebras, and Abelian Groups - Pagina 467
(a) The map associating to any left C-comodule M the underlying vector space M endowed with rational right C* -module structure defines category isomorphisms (2.2) C-ComodsDis(C") and C-comod ^ dis(C") where Dis(C') is the category of ...
Alberto Facchini, ‎Evan Houston, ‎Luigi Salce, 2004
4
Stacks and Categories in Geometry, Topology, and Algebra:
Let coAlg + comod(O) be the category of pairs (A ∈co-Algaug (O),M ∈ A-comod(O)). Note that the assignment A co-Bar• (A) can be extended to a functor (E.1) coAlg + comod(O) co-Bar•(A, M) ∈ OΔ. Moreover, this functor is (symmetric) ...
Tony Pantev, ‎Carlos Simpson, ‎Bertrand Toën, 2015
5
Introduction to the Quantum Yang-Baxter Equation and ... - Pagina 60
for all m e M and n e N. Let f : M —- M' and g : N —- N' be morphisms of Comod", that is maps of right H-comodules. Then the tensor product of linear maps f 2 g : M & N —- M' & N' is a morphism of Comod”. Observe that kVec can be thought of ...
L.A. Lambe, ‎D.E. Radford, 2013
6
Squared Hopf Algebras - Ediţia 677 - Pagina 76
[T] In the case V = k–vect this theorem was proved by Schauenburg [27]. 3.3.20. Example (Bicoalgebras obtained from ordinary Hopf algebras). Suppose that V = C = C-comod, where C is a Hopf k-algebra. How to describe the squared Hopf ...
Volodymyr V. Lyubashenko, 1999
7
Tensor Categories: - Pagina 15
This means that C := Coend(F) is a pointed coalgebra, and by Theorem 1.10.1, we have an equivalence of categories C−comod ∼= C. Moreover, suppose C is another pointed coalgebra, and G : C−comod → C−comod is an equivalence.
Pavel Etingof, ‎Shlomo Gelaki, ‎Dmitri Nikshych, 2015
8
Iuris utriusque traditio methodica: omnem omnium ... - Pagina 32
Poteft 6 auté comodato & precario dare.qui obligare fibi aliquem poteft.iuxta elo.enra de cómod.fed obligatione ufus diffe 7 runt. Nam comodatum datur ad certum ufum,ertra*quem ficommodatariuseo tiratur, obligatur ex delicto, lit fi qui* det ...
Conrad Lagus, ‎Justinus Göbler, 1553
9
Quantum Linear Groups and Representations of GL_n(F_q) - Pagina 20
We have the exact restriction functor res' comod(A) — comod(A') defined on a right A-comodule M with structure map T : M → M & A by letting res' M be the right A'-comodule equal to M as a vector space but with new structure map (id M &b) o ...
Jonathan Brundan, ‎Richard Dipper, ‎Aleksandr Sergeevich Kleshchëv, 2001
10
Free Radicals: Biology and Detection by Spinn Trapping - Pagina 303
The current induced in a loop protruding into the waveguide can be shown to be well represented by the expression / = 70(1 + m . sin (comodO) . sin (co/) = 70(sin (co/) + l/2m cos (co - comod) -l/2mcos(co + comod)) [7.40] while the main ...
Gerald M. Rosen, 1999

KAITAN
« EDUCALINGO. Cómod [online]. Kasedya <https://educalingo.com/jv/dic-ro/comod-1>. Mei 2024 ».
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