Definisi saka косинус ing bausastra Basa Rusia
COSINUS, -a, m. Fungsi trigonometri saka sudut, ing segi tiga tengen sing padha karo rasio kanggo hypotenuse ing sikil jejer menyang sudut akut iki. КОСИНУС, -а, м. . Тригонометрическая функция угла, в прямоугольном треугольнике равная отношению к гипотенузе катета, прилежащего к данному острому углу.
Klik kanggo
deleng deifinisi asli saka «косинус» ing bausastra Basa Rusia.
Klik kanggo
deleng pertalan otomatis saka definisi ing Basa Jawa.
BUKU BASA RUSIA KAKAIT KARO «КОСИНУС»
Temukaké kagunané saka
косинус ing pilihan bibliografi iki. Buku kang kakait dening
косинус lan pethikan cekak kang padha kanggo nyediyakaké panggunané ing sastra Basa Rusia.
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Lexicon Hebraico-Chaldaico-Latino-Biblicum: In Quo Prima ...
In Quo Prima Pars Omnia Vocabula, Ordine Alphabetico Disposita; ad suas Radices refert, & universas interpretationes cuique genuinas exhibet. Secunda Radices ita ordinabit, ut omnia Vocabula derivata sub his reperire liceat ... Jean-Marie ...
Jean-Marie d' Olonne, 1758
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College Trigonometry - Страница 252
Richard Aufmann, Vernon C. Barker, Richard Nation. Copyright 2008 Cengage Learning. All Rights Reserved. Copyright 2008 Cengage Learning. All Rights Reserved. Copyright 2008 Cengage. 25. 27. cos 2u cos sin 5u sin 9u u 29. cos cos u ...
Richard Aufmann, Vernon C. Barker, Richard Nation, 2007
3
Chemical Kinetics in the C-O-S and H-N-O-S Systems: A ...
A Bibliography--1899 Through June 1971 Francis Westley. I(b). II(&). COS COS COS COS COS COS COS COS COS COS COS COS COS COS COS COS COS COS COS COS COS COS COS COS COS COS COS CO2 cs* » cs 0 § § § 0 000 ...
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Text Book Of De Moivre S Theorem - Страница 103
A.K. Sharma. Example 35: 1f sin 0 + sin ф + sin iff = 0 = cos в + cos ф + cos <//, show that sin 36 + sin 3ф + sin 3ij/ = 3 sin (0 + ф + \y). and cos 39 + cos 3ф + cos 3\i/ = 3 cos (0 + ф + у). Solution : Let x = cos 0 + i sin 0, y = cos ф + i sin ф, z = cos ...
5
Rigid Body Dynamics of Mechanisms 2: Applications - Страница 640
cOs (p2) - sin ip1 - sin p2 - sin 61 + (sin ©1 - cOs (p2 - COS ©1 - sin ®2) - cOs b1 - sin ip2) - sin 62 + sin b1 - sin p2 - cOS 61 - cOs 62 +(cos q 1 - sin db2 - sin ®1 - cOs ©2) - sin b1 - cOs w2 - sin 0.1 + (sin ® 1 - sin ® + cos ...
6
The elements of analytical geometry - Страница 287
John Radford Young. 2Acos.Z + Deos.Y 4- Ecos. X cos.Z' + 2B cos.Y I cos.Y' + 2Ccos.X I cos. X' = 0 + D cos. Z + Fcos.X cos.Z" +2B cos.Y I + D cos.Z I + Fcos.X + E cos.Z + F cos.Y cos.Y" + 2Ccos.X + Ecos.Z + Fcos.Y cos. X" = 0 cos.Z" + 2B cos.
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Course In Mathematics For The Iit-Jee And Other ... - Страница A-87
Choubey K. R.. 3. (c) sin 0 + sin 20 1 + cos0 + cos26 _ sine + 2sinecos0 _ sin0(l + 2cos0) 2cos20 + cos0 cos0(2cos0 + l) = tan0 4. (b) If cos a + cos p = 0, sin a + sin p = 0 .'. a = 71 + P =>a-p = 7i cos 2a + cos 2p = 2 cos (a + P) cos (a - P) = -2cos ...
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Elementary Illustrations of the Celestial Mechanics of ... - Страница 265
Part the First, Comprehending the First Book Pierre Simon marquis de Laplace, Thomas Young. this determination relates only to the situation of the momentary axis of rotation with regard to the principal axes, and to the angular velocity of ...
Pierre Simon marquis de Laplace, Thomas Young, 1821
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Trigonometry - Том 2 - Страница 33
Anthony Nicolaides. sin 2 A = 2 sin A cos A. Consider sin(0 + O) = sin 0 cos <J> + sin <t> cos 0 If 0 = d> = A => sin (0 + <t>) = sin (A + A) sin 2A = sin A cos A + sin A cos A sin 2A = 2 sin A cos A Consider cos (0 + O) = cos 0 cos <£> — sin 0 sin ...
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Topics in Geometry - Страница 6
Om P. Chug, R.S. Dahiya. Example 6.Let cos (1+ cos B +cos 7: sin (1+ sin B + sin 7: 0. Prove that : ' (i) cos 3a + cos 3B + cos 37: 3 cos (0t + B + 7). (ii) sin 3a + sin 3B + sin 37 = 3 sin (01 + B + 7). Sol. Suppose, a = cos o:+ i sin a, b = cos B+ i sin ...
Om P. Chug, R.S. Dahiya, 2008
