«NORMALISABLE» 관련 영어 책
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If M red M' and M' is normal then we call M' a normal form of M. A term M is (
weakly) normalisable if M has a normal form and is strongly normalisable if every
contraction path M contr M' contr M" . . . is finite. Some Examples: Trivially all
normal ...
Ulrich Berger, Helmut Schwichtenberg, 1999
Let M € A be simple and
normalisable. For any a such that <pAa(a), we have that
apply ( A/, a) is simple and
normalisable, because M is simple and a
normalisable, and hence by induction hypothesis, tpAl[a](appiy(M,a)). For any a,
6 such that ...
Gerard Huet, G. Plotkin, 1991
3
Typed Lambda Calculi and Applications: Third International ...
We first introduce a translation which translates lambda-terms into lambda- I-
terms, and show that every lambda-term is strongly beta-normalisable if and only
if its translation is weakly beta-normalisable. We then prove that the translation ...
Philippe de Groote, J. Roger Hindley, 1997
4
An Approach to the Extension of a Theorem Prover by Advanced ...
normalisable. signature. morphisms. By the de nition, the mappings Σclass(T1) φ
−→ Σclass(T2), Σtype(T1) φ −→ φ Σtype(T2) and Σlogop(T1) ψ −→ φ,φ Σop(T2)
already determine the base signature morphism σ(Σlogop(T1)) : T1 −→ T2.
5
Computer Science Logic: 9th International Workshop, CSl '95, ...
This suffices to show that t is strongly normalisable, by lemma 10. — (CR2) if* —
>t', we need to show that {t'u) e REDu2 [I?/X*] for all term u C REDVl [lt/T]. Take u
C REDVl [Tt/X*]\ we have (tu) C REDu2 [T?/X*\ by definition of reducibility ...
Hans Kleine Buening, 1996
6
Confinement, Topology, and Other Non-Perturbative Aspects of QCD
Our solution corresponds to z at the boundary of this range, where the zero-mode
fails to be normalisable. This boundary value of z is defined by det(O,) = 0, and
the abelian field AQ given above corresponds to the isospin component of Oz ...
Jeff Paul Greensite, Stefan Olejna-K, 2002
7
Bayesian Time Series Models
We say that Step 4 in Algorithm 7.2 is supported, if all the beliefs that change
because of the construction of the new messages remain normalisable. On the
first forward pass this is automatically satisfied. Since a1 is a proper distribution
and B, ...
David Barber, A. Taylan Cemgil, Silvia Chiappa, 2011
8
Functional Programming and Input/Output
... take advantage of the following theorem. Theorem 2.1 (Mendler) Jf no constant
Elim" or lntro" occurs in a term M, then M is strongly normalisable, which is to say
that there is no infinite sequence of reductions starting from M. Proof. The proof ...
9
Rewriting Techniques and Applications: 10th International ...
Therefore, since the simply typed A-calculus is strongly ,3-normalisable, we
immediately obtain the following proposition. Proposition 15. AT/W is strongly
normalisable with respect to detour-conversions. I] 5 Strong Normalisation In this
section ...
Paliath Narendran, Michael Rusinowitch, 1999
Normalisable. Wave. Functions. For those wave functions which go to zero as r ->
oo or x -> ± oo the total probability has to be one i.e. Jo" Jo Jo2?t/> ('. 8.9,0 ^
smQdBity = 1 (see page 119) or j^ \^ ]^P(x,y,z,t)dxdydz = 1 (4-2-15) because the ...
