रोमानियन मध्ये COMÓD म्हणजे काय?
रोमानियन शब्दकोशातील «comód» ची
मूळ व्याख्या पाहण्यासाठी क्लिक करा.
मराठी मधील व्याख्येचे
स्वयंचलित भाषांतर पाहण्यासाठी क्लिक करा.
रोमानियन शब्दकोशातील comód व्याख्या
कॉमोड जंक्शन एम., पी एल आरामदायक; एफ. एसजी. कॉमोड, पीएल सोयीसाठी comód adj. m., pl. comózi; f. sg. comódă, pl. comóde
रोमानियन शब्दकोशातील «comód» ची
मूळ व्याख्या पाहण्यासाठी क्लिक करा.
मराठी मधील व्याख्येचे
स्वयंचलित भाषांतर पाहण्यासाठी क्लिक करा.
«COMÓD» संबंधित रोमानियन पुस्तके
खालील ग्रंथसूची निवडीमध्ये
comód चा वापर शोधा. रोमानियन साहित्यामध्ये वापराचा संदर्भ देण्यासाठी
comód शी संबंधित पुस्तके आणि त्याचे थोडक्यात उतारे.
1
Two Kinds of Derived Categories, Koszul Duality, and ... - Pagina 46
over C. The thick subcategories of absolutely acyclic CDG-comodules and CDGcontramodules are denoted by Acyclabs(C–comod) ⊂ Hot(C–comod) and Acyclabs(C–contra) ⊂ Hot(C–contra). The quotient categories Dabs(C–comod) and ...
2
Homological Algebra of Semimodules and Semicontramodules: ...
we want to compute CotorC (N•,M•) is quasi-isomorphic to the complex N• □C M• and has a one-dimensional cohomology space in every degree, even though M• represents a zero object in D(C-comod). Therefore, a more refined version of ...
3
Rings, Modules, Algebras, and Abelian Groups - Pagina 467
(a) The map associating to any left C-comodule M the underlying vector space M endowed with rational right C* -module structure defines category isomorphisms (2.2) C-ComodsDis(C") and C-comod ^ dis(C") where Dis(C') is the category of ...
Alberto Facchini, Evan Houston, Luigi Salce, 2004
4
Stacks and Categories in Geometry, Topology, and Algebra:
Let coAlg + comod(O) be the category of pairs (A ∈co-Algaug (O),M ∈ A-comod(O)). Note that the assignment A co-Bar• (A) can be extended to a functor (E.1) coAlg + comod(O) co-Bar•(A, M) ∈ OΔ. Moreover, this functor is (symmetric) ...
Tony Pantev, Carlos Simpson, Bertrand Toën, 2015
5
Introduction to the Quantum Yang-Baxter Equation and ... - Pagina 60
for all m e M and n e N. Let f : M —- M' and g : N —- N' be morphisms of Comod", that is maps of right H-comodules. Then the tensor product of linear maps f 2 g : M & N —- M' & N' is a morphism of Comod”. Observe that kVec can be thought of ...
L.A. Lambe, D.E. Radford, 2013
6
Squared Hopf Algebras - Ediţia 677 - Pagina 76
[T] In the case V = k–vect this theorem was proved by Schauenburg [27]. 3.3.20. Example (Bicoalgebras obtained from ordinary Hopf algebras). Suppose that V = C = C-comod, where C is a Hopf k-algebra. How to describe the squared Hopf ...
Volodymyr V. Lyubashenko, 1999
7
Tensor Categories: - Pagina 15
This means that C := Coend(F) is a pointed coalgebra, and by Theorem 1.10.1, we have an equivalence of categories C−comod ∼= C. Moreover, suppose C is another pointed coalgebra, and G : C−comod → C−comod is an equivalence.
Pavel Etingof, Shlomo Gelaki, Dmitri Nikshych, 2015
8
Quantum Linear Groups and Representations of GL_n(F_q) - Pagina 20
We have the exact restriction functor res' comod(A) — comod(A') defined on a right A-comodule M with structure map T : M → M & A by letting res' M be the right A'-comodule equal to M as a vector space but with new structure map (id M &b) o ...
Jonathan Brundan, Richard Dipper, Aleksandr Sergeevich Kleshchëv, 2001
9
Free Radicals: Biology and Detection by Spinn Trapping - Pagina 303
The current induced in a loop protruding into the waveguide can be shown to be well represented by the expression / = 70(1 + m . sin (comodO) . sin (co/) = 70(sin (co/) + l/2m cos (co - comod) -l/2mcos(co + comod)) [7.40] while the main ...
10
Rings, Hopf Algebras, and Brauer Groups - Pagina 140
I. A weak fc-congruence T : C* - comod -* D* - comod is a k-linear equivalence of categories such that T(C) = D. 2. A strong k -congruence T : Ce - comod -* D* — comod is a k-linear equivalence of categories such that T(A/DcAO = T(M)Ut)T(N), ...
Stefaan Caenepeel, A Verschoren, 1998
