与 «CÓMOD»相关的罗马尼亚语书籍
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1
Two Kinds of Derived Categories, Koszul Duality, and ... - Pagina 46
over C. The thick subcategories of absolutely acyclic CDG-comodules and CDGcontramodules are denoted by Acyclabs(C–comod) ⊂ Hot(C–comod) and Acyclabs(C–contra) ⊂ Hot(C–contra). The quotient categories Dabs(C–comod) and ...
2
Homological Algebra of Semimodules and Semicontramodules: ...
we want to compute CotorC (N•,M•) is quasi-isomorphic to the complex N• □C M• and has a one-dimensional cohomology space in every degree, even though M• represents a zero object in D(C-comod). Therefore, a more refined version of ...
3
Rings, Modules, Algebras, and Abelian Groups - Pagina 467
(a) The map associating to any left C-comodule M the underlying vector space M endowed with rational right C* -module structure defines category isomorphisms (2.2) C-ComodsDis(C") and C-comod ^ dis(C") where Dis(C') is the category of ...
Alberto Facchini, Evan Houston, Luigi Salce,
2004
4
Stacks and Categories in Geometry, Topology, and Algebra:
Let coAlg + comod(O) be the category of pairs (A ∈co-Algaug (O),M ∈ A-comod(O)). Note that the assignment A co-Bar• (A) can be extended to a functor (E.1) coAlg + comod(O) co-Bar•(A, M) ∈ OΔ. Moreover, this functor is (symmetric) ...
Tony Pantev, Carlos Simpson, Bertrand Toën,
2015
5
Introduction to the Quantum Yang-Baxter Equation and ... - Pagina 60
for all m e M and n e N. Let f : M —- M' and g : N —- N' be morphisms of Comod", that is maps of right H-comodules. Then the tensor product of linear maps f 2 g : M & N —- M' & N' is a morphism of Comod”. Observe that kVec can be thought of ...
L.A. Lambe, D.E. Radford,
2013
6
Squared Hopf Algebras - Ediţia 677 - Pagina 76
[T] In the case V = k–vect this theorem was proved by Schauenburg [27]. 3.3.20. Example (Bicoalgebras obtained from ordinary Hopf algebras). Suppose that V = C = C-comod, where C is a Hopf k-algebra. How to describe the squared Hopf ...
Volodymyr V. Lyubashenko,
1999
7
Tensor Categories: - Pagina 15
This means that C := Coend(F) is a pointed coalgebra, and by Theorem 1.10.1, we have an equivalence of categories C−comod ∼= C. Moreover, suppose C is another pointed coalgebra, and G : C−comod → C−comod is an equivalence.
Pavel Etingof, Shlomo Gelaki, Dmitri Nikshych,
2015
8
Iuris utriusque traditio methodica: omnem omnium ... - Pagina 32
Poteft 6 auté comodato & precario dare.qui obligare fibi aliquem poteft.iuxta elo.enra de cómod.fed obligatione ufus diffe 7 runt. Nam comodatum datur ad certum ufum,ertra*quem ficommodatariuseo tiratur, obligatur ex delicto, lit fi qui* det ...
Conrad Lagus, Justinus Göbler,
1553
9
Quantum Linear Groups and Representations of GL_n(F_q) - Pagina 20
We have the exact restriction functor res' comod(A) — comod(A') defined on a right A-comodule M with structure map T : M → M & A by letting res' M be the right A'-comodule equal to M as a vector space but with new structure map (id M &b) o ...
Jonathan Brundan, Richard Dipper, Aleksandr Sergeevich Kleshchëv,
2001
10
Free Radicals: Biology and Detection by Spinn Trapping - Pagina 303
The current induced in a loop protruding into the waveguide can be shown to be well represented by the expression / = 70(1 + m . sin (comodO) . sin (co/) = 70(sin (co/) + l/2m cos (co - comod) -l/2mcos(co + comod)) [7.40] while the main ...