QUE SIGNIFIE CÓMOD EN ROUMAIN
définition de cómod dans le dictionnaire roumain
cómod, -Ă adj. (large cómmodus). Facile à utiliser Calme et agréable: un cody. Nice et gentil. Détendu, pas trop austère: moralement humoristique. Adv. Cody. \u0026 # X2013; Fals comód (après le Commode).
10 LIVRES EN ROUMAIN EN RAPPORT AVEC «CÓMOD»
Découvrez l'usage de
cómod dans la sélection bibliographique suivante. Des livres en rapport avec
cómod et de courts extraits de ceux-ci pour replacer dans son contexte son utilisation littéraire.
1
Two Kinds of Derived Categories, Koszul Duality, and ... - Pagina 46
over C. The thick subcategories of absolutely acyclic CDG-comodules and CDGcontramodules are denoted by Acyclabs(C–comod) ⊂ Hot(C–comod) and Acyclabs(C–contra) ⊂ Hot(C–contra). The quotient categories Dabs(C–comod) and ...
2
Homological Algebra of Semimodules and Semicontramodules: ...
we want to compute CotorC (N•,M•) is quasi-isomorphic to the complex N• □C M• and has a one-dimensional cohomology space in every degree, even though M• represents a zero object in D(C-comod). Therefore, a more refined version of ...
3
Rings, Modules, Algebras, and Abelian Groups - Pagina 467
(a) The map associating to any left C-comodule M the underlying vector space M endowed with rational right C* -module structure defines category isomorphisms (2.2) C-ComodsDis(C") and C-comod ^ dis(C") where Dis(C') is the category of ...
Alberto Facchini, Evan Houston, Luigi Salce,
2004
4
Stacks and Categories in Geometry, Topology, and Algebra:
Let coAlg + comod(O) be the category of pairs (A ∈co-Algaug (O),M ∈ A-comod(O)). Note that the assignment A co-Bar• (A) can be extended to a functor (E.1) coAlg + comod(O) co-Bar•(A, M) ∈ OΔ. Moreover, this functor is (symmetric) ...
Tony Pantev, Carlos Simpson, Bertrand Toën,
2015
5
Introduction to the Quantum Yang-Baxter Equation and ... - Pagina 60
for all m e M and n e N. Let f : M —- M' and g : N —- N' be morphisms of Comod", that is maps of right H-comodules. Then the tensor product of linear maps f 2 g : M & N —- M' & N' is a morphism of Comod”. Observe that kVec can be thought of ...
L.A. Lambe, D.E. Radford,
2013
6
Squared Hopf Algebras - Ediţia 677 - Pagina 76
[T] In the case V = k–vect this theorem was proved by Schauenburg [27]. 3.3.20. Example (Bicoalgebras obtained from ordinary Hopf algebras). Suppose that V = C = C-comod, where C is a Hopf k-algebra. How to describe the squared Hopf ...
Volodymyr V. Lyubashenko,
1999
7
Tensor Categories: - Pagina 15
This means that C := Coend(F) is a pointed coalgebra, and by Theorem 1.10.1, we have an equivalence of categories C−comod ∼= C. Moreover, suppose C is another pointed coalgebra, and G : C−comod → C−comod is an equivalence.
Pavel Etingof, Shlomo Gelaki, Dmitri Nikshych,
2015
8
Iuris utriusque traditio methodica: omnem omnium ... - Pagina 32
Poteft 6 auté comodato & precario dare.qui obligare fibi aliquem poteft.iuxta elo.enra de cómod.fed obligatione ufus diffe 7 runt. Nam comodatum datur ad certum ufum,ertra*quem ficommodatariuseo tiratur, obligatur ex delicto, lit fi qui* det ...
Conrad Lagus, Justinus Göbler,
1553
9
Quantum Linear Groups and Representations of GL_n(F_q) - Pagina 20
We have the exact restriction functor res' comod(A) — comod(A') defined on a right A-comodule M with structure map T : M → M & A by letting res' M be the right A'-comodule equal to M as a vector space but with new structure map (id M &b) o ...
Jonathan Brundan, Richard Dipper, Aleksandr Sergeevich Kleshchëv,
2001
10
Free Radicals: Biology and Detection by Spinn Trapping - Pagina 303
The current induced in a loop protruding into the waveguide can be shown to be well represented by the expression / = 70(1 + m . sin (comodO) . sin (co/) = 70(sin (co/) + l/2m cos (co - comod) -l/2mcos(co + comod)) [7.40] while the main ...